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Match Details
Date: 8th May 2021
Time: 12:30 AM (IST)
Venue: Vinor Cricket Ground, Prague
News: SportsTiger App
Preview
Prague CC Rooks will be up against Brno Rangers in match 21 of the ongoing ECS T10 Prague 2021 tournament at the Vinor Cricket Ground on Saturday. While Brno Rangers are currently at the top of the table with three wins from three matches, Prague CC Rooks is at the bottom of the Group B tally with two losses in two matches. Thus, while Rangers will look to carry forward their momentum, Rooks would look to open their account with their first win.
Weather Report
Pitch Report
Analysis
Naveen Padmaraju will hold the key for the Prague CC Rooks. Not only has he been in good form with the ball as was evident with his 3/9 in the opening match, but he is also capable of fetching points with the bat as well. Meanwhile, Rohit Deshmoyni was the top wicket-taker at ECN Czech Super Series Week 3 with close to eight wickets to his tally with a best of 3/7 and should be included in the fantasy side. Similarly, one cannot afford to miss out on Rahat Ali and Tripuarai Lal in the Fantasy side.
Key Players
Probable Playing XI
Prague CC Rooks
Naveen Padmaraju (c), Jeet Shah (wk), Christopher Tebb, Karthick Gopalakrishnan, Vinod Suthar, Naveen Gunasekaran, Kasi Viswanathan, Rohit Deshmoyni, Jinnu Panilet, Dipankumar Patel, Jahangir Wani
Brno Rangers
Dylan Steyn (c), Ushan Gunathilake (wk), Sandeep Tiwari, Tripurari Kanhya Lal, Jan Hoffmann, Somsuvro Basu, Ali Kashif, Vikram Padigala, Somesekhar Banerjee, Naveed Ahmed, Rahat Ali
Team 1
Team 2
Best 13
Wicketkeepers: J Hoffmann, Ushan Gunathilake, Jeet Shah
Batsmen: D Steyn, A Kashif, KV Balakrishnan,
All-rounders: R Ali, Z Tariq, N Padmaraju, N Gunasekaran
Bowlers: T K Laal, S Basu, R Deshmoyni
Disclaimer: The fantasy tips and facts expressed within this article are personal opinions of the author. They do not reflect the views of SportsTiger. It is not a reflection of the actual points you might earn. SportsTiger does not assume any responsibility or liability for the same.
